Option D will be the correct diagram. Weight of the system will act vertically downward. The reaction force will act upward along the Cos component of weight. This reaction force will be divide equally in two tyre along the centre of the tyre. Since the cycle is rolling down the friction between tyre and surface will act opposite to the motion . And the air drag Fair will act opposite and parallel to the motion. Thus the option D will satisfy.
Consider four cases displaying the free-body diagram of a cyclist on a bicycle rolling Case A Case B down a hill (...
1. Consider a sky diver in free fall (a) Draw a free body diagram showing the forces acting on the sky diver. Note that the drag force will be proprtional to velocity squared, and act in the opposite direction to velocity. (b) Apply Newton's 2nd Law to model the skydiver's velocity with a 1st order ODE, treating down as the positive direction. Present your ODE in standard form (c) A skydiver has a mass of 90 kg, and a drag...
4) Read the following and revise your free body diagram as necessary A common confusion when drawing extended free body diagrams is how to draw the force of gravity. For a static equilibrium situation like this, you should draw a single arrow to represent the force of gravity on an extended object. The tail of this vector is placed at the center of mass of the object. It is good practice to pause at this point and think about whether...