Question

The dra elow shows a mixture of molecules: key carbon o hydrogen nitrogen O sulfur oxygen chlorine Suppose the following chemical reaction can take place in this mixture: 2 S(s)+302(g) → 280z(9) Of which reactant are there the most initial moles? Enter its chemical formula: Of which reactant are there the least initial moles? Enter its chemical formula: Which reactant is the limiting reactant? Enter its chemical formula:

Answer 1

6 moles sulfur

10 moles of oxygen

2S(s) +3 O2(g) ------------> 2SO3(g)

oxygen has more moles initial   : chemical formula : O2

sulfur has least moles initial : chemical formula : S

3 moles of O2 react with 2 moles of sulfur

10 moles of O2 react with = 2*10/3   = 6.67 moles of sulfur is required

S is limiting reactant chemical formula : S