Question

Your program must meet the following specifications: 1. At program start, assume a stock of 10 nickels, 10 dimes, 10 quarters, and 10 pennies. 2. Repeatedly prompt the user for a price in the form xX.xx, where X denotes a digit, or to enter q' to quit 3. When a price is entered a. If the price entered is negative, print an error message and start over requesting either a new price or to quit (indicated by entering a 'q) b. Prompt for the number of dollars in payment. If the payment is insufficient, print an error message and reprompt for payment. c. Next determine the coins to be dispensed as change. This calculation will depend on the amount to be dispensed and also on the number of coins left in the stock. For example, the least number of coins needed to make change of $1.30 is 6: 5 quarters and 1 nickel. But if there are only 3 quarters, 3 dimes, and 10 nickels left in the stock, then the least number is 11: 3 quarters, 3 dimes, and 5 nickels. d. Print the numbers of the coins to be dispensed as change and their denominations. (Omit a denomination if no coins of that denomination will be dispensed.) e. In case exact payment is made, print a message such as "No change. f. If the change cannot be made up with the coins remaining, print an error message and halt the progranm Just before quitting, print the total amount (the number of dollars and number of cents) left in the stock. 4. Notes and Hints: 1. To clarify the project specifications, sample output is appended to the end of this document. 2. Items 1-6 of the Coding Standard will be enforced for this project. We provide a proj02.py program for you to start with. It has a simple while loop (notice how input is prompted before the loop and at the bottom of the loop 4. 3. Floating point numbers can be difficult to work with due to the imprecision of representing real numbers in a finite number of computer-memory bits. To avoid imprecision do your calculations in cents, i.e. as type int. For example, $1.15 is the same as 115 cents. To see the problem, try evaluating 1.15*100 in the Python shell and compare that to evaluating round (1.15*100) 5. There are many ways to calculate the maximum number of quarters to make change using the greedy algorithm a. One is with a while loop where you keep subtracting 25 from the amount of change due and increment the number of quarters. End the loop when there are less than 25 cents due or you are out of quarters. After determining quarters you can determine dimes in the same way, e.g. using 10 instead of 25. Work your way down through the other coins b. Alternatively, use the quotient (I) operation for integers for finding the numbers of each coin. For example, 195//25 is 7, the most number of quarters in 195 cents. However, be careful: if the stock has fewer than 7 quarters left, you will only be able to dispense the number left in the stock. For example, if there are only 6 quarters left, then you can dispense only 6 quarters and must use dimes and nickels to make up any remaining change. When we learn about formatting strings, we can more easily and elegantly print monetary amounts. For now, just use the Python print(...) command with appropriate string and/or integer arguments to print the number of dollars and the number of cents 7. 6. One tricky control issue is how to end the program if you run out of coins in the stock. The sample proj02.py program provides a clue with the empty_stock Boolean. The problem is that break only breaks out of the current, innermost loop whereas you may be within multiple loops so when you break you can set the empty_stock Boolean to True and use that to break out of the enclosing loops 8. You do not need to check for any input errors other than those mentioned in this description 9. You may not use advanced data structures such as lists, dictionaries, sets or classes in solving this problem # purchase price and payment will be kept in cents quarters10 dimes 10 nickels10 pennies 10 print "WnWe Icome to change-mak ing program.") print "WnStock: quarters, dimes, nickels, and pennies" .format quarters, dimes, nickels, pennies)) in_strinput("Enter the purchase price (xx.xx) or 'q' to quit:" while in_str- 'q' # Fill in the good stuff here instead of the following print pr int("Testing: ", in_str) pr int("WhStock: quarters, 0 dimes, quarters, dimes, nickels, pennies)) nickels, and pennies" .format( in strinput( "Enter the purchase price (xx.xx) or 'q' to quit: ")

Answer 1

Code

quarters=10
dimes=10
nickels=10
pennies=10

print('Welcome to the chenage-making program')
print('Stock : {} quarters, {} dimes, {} nickels, and {} pennies'.format(quarters,dimes,nickels,pennies))

while True:
int_str=input("\nPlease enter the price in form of XX.XX or q to stop: ")
if(int_str=='q'):
break
price=float(int_str)
if(price>0):
break
else:
print('Please enter the positve value.')

while(int_str!='q'):
while True:
dollar=float(input('\nEnter the number of dollar for payment: '))
if(dollar>price):
price=price*100
dollar*=100
break
else:
print('Insufficient amount!!')

noOfQuarters=0
noOfDimes=0
noOfNickels=0
noOfPennies=0
change=dollar-price
print('Your change is $',(change/100))
noOfQuarters=int(change/25)
if(noOfQuarters<=quarters):
quarters-=noOfQuarters
change-=noOfQuarters*25
else:
noOfQuarters=quarters
quarters=0
change-=noOfQuarters*25

noOfDimes=int(change/10)
if(noOfDimes!=0):
if(noOfDimes<=dimes):
dimes-=noOfDimes
change-=noOfDimes*10
else:
noOfDimes=dimes
dimes=0
change-=noOfDimes*10

noOfNickels=int(change/5)
if(noOfNickels!=0):
if(noOfNickels<=nickels):
nickels-=noOfNickels
change-=noOfNickels*5
else:
noOfNickels=nickels
nickels=0
change-=noOfNickels*5

noOfPennies=change
if(noOfPennies!=0):
if(noOfPennies<nickels):
pennies-=noOfPennies
else:
noOfPennies=nickels
pennies=0

totalCoin=noOfDimes+noOfNickels+noOfPennies+noOfQuarters
print('\nLeast number of coin needed to change is {}'.format(int(totalCoin)))
if(noOfQuarters!=0):
print('{} quarters'.format(noOfQuarters))
if(noOfDimes!=0):
print('{} dimes'.format(noOfDimes))
if(noOfNickels!=0):
print('{} nikckles'.format(noOfNickels))
if(noOfPennies!=0):
print('{} pennies'.format(noOfPennies))

print('\nStock : {} quarters, {} dimes, {} nickels, and {} pennies'.format(quarters,dimes,nickels,pennies))

while True:
int_str=input("\n\n\nPlease enter the price in form of XX.XX or q to stop: ")
if(int_str=='q'):
break
price=float(int_str)
if(price>0):
break
else:
print('Please enter the positve value.')

outputs

code snaps

If you have any query regarding the code please ask me in the comment i am here for help you. Please do not direct thumbs down just ask if you have any query. And if you like my work then please appreciates with up vote. Thank You.