Question

solve using kinetic energy equations. ( Theorem of change in kinetic enegery)

KE20. Figure shows a mechanism. Body 5 is assumed to be homogeneous circular cylinder, and mass of the pulley 4 is uniformly distributed over its rim. The coefficient of sliding friction between bodies and the plane is f 0.1 The coefficient of stiffness of a spring is c. A force F applied to the mechanism depends on the displacement s of the body 1. The mechanism starts motion from rest, and at the beginning of the motion the spring is unstretched. 5 30 During the motion the constant moment of resistance M is acting on the pulley 3. Find the angular velocity ws of the pulley 3 at the instant when s 0.2 m. Parameters: R 0.3 m, 0.1 m, and radius of gyration ps 0.2 m, R 0.2 m, m0 kg, m 5 kg, 4 kg. ma-0 kg, n15 6 kg, c-200 N/m, M-1.5 Nm. F 85(4+5si) N. 60°

Answer 1

2- 40.2 1. C1+55)) X85 k200 N/m BD-2 23 32 Soo 49

nl 父 60 in Go ク(- 2 F24sin 30s 3 o sin Cso) 45 " F2年こ9311 Noa 反3 ニ s-3 41 4.24 24-5 + 5

.301 60 F. 32 3 3o) sin (360 40) io) sin6o 32= 245 373 8-N F32= 245.4N 5 a= 24.64 m R= 101.46 Nm

2 d-101-4534 12e 0.2 2页 S) CO 0 666 66