If the normal boiling point of a liquid is 67 ?C, and the standard molar entropy change for the boiling process is +100...
If the normal boiling point of a liquid is 67 ?C, and the standard molar entropy change for the boiling process is +100 J/K, estimate the standard molar enthalpy change for the boiling process.
A. +6700 J
B. -6700 J
C. +3400 J
D. -3400 J
If you could show your work and explain that would be great.
Thank you!
Homework Answers
We can the value of the standard molar enthalpy change for the boiling process fron the following relation.
Boiling point of a liquid (Tb), standard molar entropy change for the boiling process (DeltaS0 ) and standard molar enthalpy change for the boiling process (DeltaH0 ) are related through the following equation.
DeltaSvap = DeltaHvap /Tb
Given Tb = 67 degC = 273+67 = 340K and DeltaSvap = +100JK-1
=> DeltaHvap = DeltaS0 xTb = +100 JK-1 x 340K = +34000 J (answer)
Here the correct answer is +34000 J , which is not in the option. So check all the options whether they are written correctly.
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