Question

Carbon monoxide (CO) is toxic because it binds more strongly to the iron in hemoglobin (Hb) than does oxygen (O2), as indicated by these approximate standard free-energy changes in blood:

Hb+O2=HbO2 Delta G= -70 kJ/mol
Hb+CO=HbCO Delta G= -80 kJ/mol

Part A
Estimate the equilibrium constant K at 298 K for the equilibrium

HbO2+CO==HbCO+O_2

Answer 1

Answer 2

reaction A $+\(H_{b}+O_{2}+->HbO_{2}\)+$ = $+\(\Delta+G+=+-70kJ/mol\)+$ needs to be reversed to match the equation equilibrium givin, making $+\(\Delta+G+=+70+kJ/mol\)+$ then you add the two equations together to get the overall $+\(\Delta+G\)+$ . $+\(overall+\Delta+G+=70+kJ/mol+++-80kj/mol+=+-10kJ/mol\)+$ Then using the quation

$+\(\Delta+Gnot=-RTln(k)\)+$ solving for K.

$+\(e^{\Delta+G/-RT}=K\)+$ we get $+\(e^{-10/-8.314x10^{-3}kj/mol*s98K}=56.26\)+$

or $+\(\approx+60\)+$