As in the process pressure remains constant, which mean that the we are dealing with isobaric process.
The work done for isobaric process can be given as below,
Work done (W) = P x (V2-V1)
Here, V2= 350 mL = 0.35 L, V1 = 50 mL =0.05 L and P = 0.5 atm
Work done (W) = 0.5 x (0.35 L - 0.05 L) = 0.15 L atm
As , 1 L atm = 101.3 J
0.15 L atm = 0.15 x 101.3 = 15.2 J
Therefore, answer is, a. 15.2 J.
19. of 50.00 mL to a volume of 3 50.00 mL? (101.3 J = 1 Latm) A-(PAV) wolk c. -15.2J d. -0.152 J a. 15.2 J b. 0.150...
1. A volume of water was heated to 83.90 °C and immediately added to 48.11 mL of water at 23.98 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 40.86 °C. The final volume of water inside the calorimeter was 90.45 mL. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: a. The volume of hot water added ml b. The mass of hot water (dwater = 1.00 g/mL) c....
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8,9,10,&11
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1) the kinetic energy of a 15.2 kg object traveling at 8.49 m/s is ___ J. 2) A 437.2 g sample of an unknown substance requires 8460 J to increase its temperature from 19.3 oC to 68.9 oC. The specific heat of the substance is ___ J/g oC. 3) A 437.2 g sample of an unknown substance requires 8460 J to increase its temperature from 19.3 oC to 68.9 oC. According to table 5.1 in the text, the sample may...
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i need help with number 8 and 9 please!
297 Experiment 24 10. Common ion effect a. Concentration of KHT final solution (50 mL) b. Volume of solution c. Mass of KCI d. Concentration of KCI 5.0x10 mL 271 381 f. Total [H [KHned g. Saturation temperature (C) h. Saturation temperature (K) 516 332.7S 0428 j. Why did the temperature have to be increased to dissolve the KHT when the KCI was added? B. K, by titration. 10.1:C 1. Temperature...
3. A sample of gas occupies a volume of 600 mL. As the expands, it does 202 J of work on its surroundings at a constant pressure of 1.25 atm. What is the final volume of the gas in ml? e) 162200 mL a) 162 mL b) 1600 mL c) 2200 mL d) 161600 mL
part c and d please ?
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