Question

The maximum amount of barium chromate that will dissolve in a 0.290 M potassium chromate solution is

ksp for barium chromate: 2.0x10^-10

Answer 1

The concentration of K₂ Croy = 0.290m. So concentration of crou = 0.290 m Bacrou Ž Baht + choy Let x . mole Bacnou can dissolve maximum. x mole Ba chou produce a mole Bart and a mole crou So in the solution, the final concentration of [Ba2+] = x mole Final concentration of [crou] = (0.290tk) So [Batt] [ enoga] = kap. on x. (0.290 + x) = 2x1010 x² + 0.290 x – 2x1510 =0 x = 6.89 x 1510 M So the maximum amount of Barium chromate in 6.89 x 1010 m.