(A)
Budget constraint: 168 = 8X + 3Y
When X = 0, Y = 168/3 = 56 (vertical intercept) and when Y = 0, X = 168/8 = 21 (horizontal intercept).
Slope = - Px/Py = -8/3 = - 2.67
In following graph, AB is the budget line.
(B)
MUx = U/X = 8X3Y3
MUy = U/Y = 6X4Y2
MRS = MUx/MUy = (8X3Y3) / (6X4Y2) = (4/3).(Y/X) = 4Y / 3X
(C)
If MRS = 4, it means that consumer is willing to give up 4 units of Y in order to consume 1 additional unit of X.
(D)
Utility is maximized when MRS = Px/Py
4Y / 3X = 8/3
12Y = 24X
Y = 2X
Substituting in budget line,
168 = 8X + 3Y
168 = 8X + (3 x 2X)
168 = 8X + 6X = 14X
X = 12
Y = 2 x 12 = 24
In above graph, utility is maximized at point E where indifference curve IC0 is tangent to AB with optimal bundle (X0, Y0) = (12, 24).
- H u y | | | | - 2. Xin is a foodie and loves to spend all his money on food(x) and drinks(Y). As we know, the pric...
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