calculate the hydronium and hydroxide concentrations of a solution with a pH of 4.5, one with a pH of 7, and another with a pH of 12.63
As we know that, pH=-log(H3O+)
[H3O+]=10^-pH and [OH-]=10^-pOH
And [H3O+][OH-]=1x10^-14
pH+pOH=14
pH=14-pOH
1. pH=4.5, pOH=14-4.5=14-4.5= 9.5
[H3O+]= 10^-4.5= 3.16x10^-5 M
[OH-]=10^-9.5= 3.16x10^-10 M
2. pH=7
[H3O+]= 10^-7 M
pOH=14-7=7
And [OH-]=10^-7 M
pH=12.63
pOH=14-12.63= 1.37
[H3O+]= 10^-12.63= 2.34x10^-13 M
[OH-]= 10^1.37=4.26x10^-2 M
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