A 25.0 mL analyte is made up of 0.230 g of an unknown monoprotic acid. The equivalence point is reached after 22.5 mL of...
A 25.0 mL analyte is made up of 0.230 g of an unknown monoprotic acid. The equivalence point is reached after 22.5 mL of a 0.050 M NaOH solution is titrated into the analyte. Based on the following determine
a. The initial concentration of the unknown acid.
b. The molar mass of the unknown acid.
Please show all steps and work!! I am so confused
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