A wild-type trihybrid soybean plant is crossed to a pure-breeding soybean plant with the recessive phenotypes pale leaf...
A wild-type trihybrid soybean plant is crossed to a pure-breeding soybean plant with the recessive phenotypes pale leaf l, oval seed (r), and short height (t). The results of the three-point test cross are shown in the table. Traits not listed are wild type.
A) Place the alleles in their correct gene order. Use L, R, and T to represent dominant alleles and l, r, and t for recessive alleles.
L-T-R
L-R-T
T-L-R
B) Calculate the recombination fraction between T and L pair of genes.
C) Calculate the recombination fraction between T and R pair of genes.
D) Calculate the interference value for these data
Please include explanation!
| Phenotype | Number |
| Pale | 648 |
| Pale, oval | 64 |
| Pale, short | 10 |
| Pale, oval, short | 102 |
| Oval | 6 |
| Oval, short | 618 |
| Short | 84 |
| Wild type | 98 |
| 1630 |
Homework Answers
|
Phenotype |
Number |
|
Pale |
648 --> Parental |
|
Pale, oval |
64 -----> Single recombinant (recombination between T and R) |
|
Pale, short |
10 ----> Double recombinant |
|
Pale, oval, short |
102 ---> Single recombinant (recombination between T and L) |
|
Oval |
6 -------.> Double recombinant |
|
Oval, short |
618 ---> Parental |
|
Short |
84 ---> Single recombinant (recombination between T and R) |
|
Wild type |
98 ----------> Single recombinant (recombination between T and L) |
|
1630 |
A). From the given table, the genotype of the parents is lTR and Ltr. Double cross over gave the offspring with the phenotypes oval and plale, short. Thus, the gene order is L-T-R.
B). Calculate the recombination fraction between T and L pair of genes. = number of gametes produced by single crossover of T and L + number of double crossover gametes*100/ total number of gametes.
= [(102+98) + (10+6)]* 100/ 1630 = 13.25 map units.
The genetic distance between genes T and L = 13.25 map units.
C). The recombination fraction between T and R pair of genes. = number of gametes produced by single crossover of T and R + number of double crossover gametes*100/ total number of gametes.
= [(64+84) + (10+6)]* 100/ 1630 = 10.06 map units.
The genetic distance between genes T and R = 10.06 map units.
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