Question

A wild-type trihybrid soybean plant is crossed to a pure-breeding soybean plant with the recessive phenotypes pale leaf...

A wild-type trihybrid soybean plant is crossed to a pure-breeding soybean plant with the recessive phenotypes pale leaf l, oval seed (r), and short height (t). The results of the three-point test cross are shown in the table. Traits not listed are wild type.

A) Place the alleles in their correct gene order. Use L, R, and T to represent dominant alleles and l, r, and t for recessive alleles.

L-T-R

L-R-T

T-L-R

B) Calculate the recombination fraction between T and L pair of genes.

C) Calculate the recombination fraction between T and R pair of genes.

D) Calculate the interference value for these data

Please include explanation!

Phenotype Number
Pale 648
Pale, oval 64
Pale, short 10
Pale, oval, short 102
Oval 6
Oval, short 618
Short 84
Wild type 98
1630
0 0
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Answer #1

Phenotype

Number

Pale

648   --> Parental

Pale, oval

64     -----> Single recombinant (recombination between T and R)

Pale, short

10 ----> Double recombinant

Pale, oval, short

102 ---> Single recombinant (recombination between T and L)

Oval

6 -------.> Double recombinant

Oval, short

618 ---> Parental

Short

84 ---> Single recombinant (recombination between T and R)

Wild type

98 ----------> Single recombinant (recombination between T and L)

1630

A). From the given table, the genotype of the parents is lTR and Ltr. Double cross over gave the offspring with the phenotypes oval and plale, short. Thus, the gene order is L-T-R.

B). Calculate the recombination fraction between T and L pair of genes. = number of gametes produced by single crossover of T and L + number of double crossover gametes*100/ total number of gametes.

= [(102+98) + (10+6)]* 100/ 1630 = 13.25 map units.

The genetic distance between genes T and L = 13.25 map units.

C). The recombination fraction between T and R pair of genes. = number of gametes produced by single crossover of T and R + number of double crossover gametes*100/ total number of gametes.

= [(64+84) + (10+6)]* 100/ 1630 = 10.06 map units.

The genetic distance between genes T and R = 10.06 map units.

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