Could you explain why too? Thank you.
Zn(OH)2 is more soluble in an acidic solution than in pure water.
Explanation:
Conjugate base of a weak acids like hydroxide, carbonate, acetate, phosphate etc increases its solubility in presence of acidic solutions.
Zn(OH)2(s)⇌Zn2+(aq)+2OH−(aq)
In presence of acid the insoluble hydroxide will form the bellow reaction of
H+(aq)+OH−(aq)→H2O(l)
Thus overall reaction will be
Zn(OH)2(s)+2H+(aq)⇌Zn2+(aq)+2H2O(l)
So according to Le-Chatelier’s principle more acid will favor more product so equillibrium will shift towards right side making Zn(OH)2 more soluble in acidic solution.
Could you explain why too? Thank you. Which of the compounds is more soluble in an acidic solution than in pure water? C...
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