Question

7. Two elements, chocolatonium (Ch) and aprilium (Ap), combine to form several compounds. Two of these are ChAp2 and ChaAps. A sample of ChaAps contains 275 g Ch and 433 g Ap. a. Find the relative mass of Ch to Ap in Ch2Aps. b. Find the relative mass of Ch to Ap in Ch2Aps if the mass of Ap is exactly 45 amu. c. How many grams of Ch can combine with 126 g Ap in ChaAps using the new adjusted relative mass. d. If a 133.4 g sample of chocolatonium aprilide had 8.55 x 1026 atoms total, find the number of chocolatonium atoms in a 26.5 g sample. Hint: how many atoms of chocolatonium in one formula of Ch2Aps.

Answer 1

7. a) Consider ch₂ Aps Given: ch-0459, Ap=4339 relative mass of ch to Ap = 2759-10.635le] I 4339 b) cha Aps when Ap- 45am 1x 10mg = 74.745*10 relative mass of ch to Ap= 275g -3.68x1024 74,745x10 g c) 126g Ap in Che Aps (3.68x16 4p of ch combines with Ap (45 amu: 74.745x1024) 8. 126g of Ap combines with ag of Ch. 126x3.68x10424 740745 x 16 4 45x tot = 463.68x1024) d) ch, AP has 8.55 x 102 atoms in 133.4g. 26.59 sample contains 26.5x8.55 X 10% atons 133.4 1.698% 1026 atoms. In 1 mole of ch, Aps, a moles of ch. But I molecule of Ch, Aps has a atoms of Ch f5 atoms of Af o out of to 698 x 10 h atoms of chaps, a parts constitutes. chatons. which is 2x10698 X10 - 0.48514+10% atoms. 26 26