Question

Can someone help answer these?

9. Percent yield a. In an experiment to prepare sodium acetate, the theoretical yield is 105,0 g. If the actual yield is 99.8 g, what is the percent yield? b. You have calculated that you should obtain 567.3 g of Al from Al2O3. You only obtained 492.2 g. What was your percent yield? c. If you should have gotten 98.5 g of CaCO3 from an experiment and this represented a 75.0% yield, what was the actual amount that you got? och Woollomos os b logs who woyilis bau Woodlalom Voodbloomsbord oll

Answer 1

92.011 gimo) solution ;-que. vield - Actual yield x 100 Coy Thoertical yield = 105-09 Theertical Yield Actual yield = 99.89 - yield = 99.89 x100 795.05% Ango 10500 g (b) Thoertical yield=567.39 Actual yield=492.2g to yield = 492.28 X100 + 86-76% Ansa 567.39 Thoertical yielel = 98.59 to yield = 75% 50Actual yield = 75 X9859 -> 73.879 Ane 100 molqy mass Formula -oue-6 name sufuric acid H2 504 Dinitrogen te toqoxice N₂O4 chromium (111) nitride CON 66.00g/mol Calcium phosphate cqz (PO4)2 53.4913lmo) Ammonium chloride NH4c Strontium bicarbonate S8003 147.63g/mo) Que? Balence Reaction:- 4 Fe +302 270,0z (4) According to balance Reaction 2 mole Fezoz Brodece by 4 mol Fe. 1. I mole Fezoz Produce by 4 mole fe so. 8 molfe Produce - 4 mole fe₂O3 ans (6) Accoreling to Reacten 4 mole fe React with 3 mole Oz į mole fe React with 3 moleo, 2 mole fe React with 3x2 mole a mole of oz used with 2 mole fe = 105 mol Que 8: Balance Reaction'ir (641206 +6026 co,+ 6H₂O t' I mole Gulcose produce 6 mole CO2 so 18 mol CO2 Produce by 18 mol Gulcase = 3 mol Gulcose Ane 310.18 g/mol

(b) Accareling to Reaction 6 mole H20 Produce by 1 mol Gulcose I mole H₂o Produce by t mol Gulcose 1. So 0.5 mol Gulcose is produce = 0.5X6 mol H₂O = 3 mol H2O me Que 5. (a mn m net the rxn type oxidation - Nibe N3- rentype Reduction. b) ang to engo ola +ż-2 mg Oxidized oxidizing agent O2 mg oxidized from o to +2 - Reducing agent - mg o reduced o Reduced from o to -2 © Ca + Cl2 Cacha Ga oxidized oxidizing agent cla ca oxidized from o to 42 Reducing agent ca C12- Reduced cle Reduced from oto-2