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Answer #1

Since, at statel the water is in liquid state, the specific volume and intemal energy -(T-00F -0.02043ft3lb uf T-500°F -485.1680x144(0.6761-0.02043) 12-1117.4-485.1) + 778 = 1.5×714.82 2 1072.235 Btu W12 = 1.5×82.523 -123.78Btu For process 2-3 SinceFrom properties of saturated water temperature tables: AtT 100°F P 0.9503lbf /in.2 he-68.05 Btu/lb 3-11 05.0Btulb «, 1043.5 BThermal effici ency, = 1-560 960 = 0.4166 41.66%

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