Question

Consider the following reaction carried out in liquid 2A+3B- Table Q1.1 lists the initial rate of reaction for the initial concentration of A and B Table Q1.1: Initial reaction rate, vo [mol/m'.s] (IC, 0.000 [mol/m') Initial concentration of A, [Al, [mol/m 10.00 20.00 50.00 316.23 Initial 28.28 20.00 89.44 1000.0 concentration 25.00 of B, 75.00 [Bl, [moVm'] In (a) Show the reaction rate of C, ve, by using krfvi, [4], [3] (6 marks) POI/CO1/C3) (b) Evaluate the rate constant, k,, and the orders in A and B, n and m (6 marks) (PO2/CO2/C4) (c) Estimate a value of the initial reaction rate, X. (4 marks) (PO3/CO3/C5) (d) Calculate a value of the initial concentration of A, Y (4 marks) (PO2/CO2/C4) (e) Evaluate the concentration of B and C, [3] and [C, for [A-8.00, [41.-10.00 and [Blo 20.00 [mo/m']. (10 marks) (PO3/CO3/C5)

Answer 1

Answer:

According to the problem given, we have reaction rates for various initial concentrations of [A] and [B].

reactionrate-TET dt 3 dt

The negative sign is for the reactants and the positive sign is for the products

Now, We need to find out the exponents: m & n

Taking the first two cases:

when [B] = 20
mol/m
and [A] = 10
mol/m
: reaction rate = 28.28
mol/m3s

and when [B] = 20
mol/m
and [A] = 50
mol/m
: reaction rate = 316.23
mol/m3s
  

------------------ (i)

28.28- kr10m20

---------------- (ii)

316.23 k5020

dividing (i) and (ii)

31623-5/n-11.18 28.28

m = 1.5 [ Answer]

Putting above value, Lets find n

when [B] = 20
mol/m
and [A] = 10
mol/m
: reaction rate = 28.28
mol/m3s

and when [B] = 25
mol/m
and [A] = 20  
mol/m
: reaction rate = 89.44
mol/m3s
  

25 89.4421.5[^jn 28,28-2 120

,1.52. In = 3.162 89.44

n= 0.5 [ Answer]

Now, We have to find  $k_{r}$

28.28 =

,110|1.5200.5

[Answer]

A-= 0.199