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Even at high temperatures, the formation of NO is not favored: (Kc = 4.10 ×10−4 at 2000°C) N2(g) + O2(g) ⇌ 2 NO(g) What...

Even at high temperatures, the formation of NO is not favored:
(Kc = 4.10 ×10−4 at 2000°C)

N2(g) + O2(g) ⇌ 2 NO(g)
What is [NO] when a mixture of 0.20 mol of N2(g) and 0.17 mol of O2(g) reach equilibrium in a 1.0−L container at 2,000°C?

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Answer #1

0.20 mor = 0.20 M [2) = Tool [02] = Oolt moe - Oolfa 1.0 N2 (9) + O2 (9) 7 21019) ſ 0.20 0.17 c -a -n 2a E 10.20-a) (0.14-a)

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Even at high temperatures, the formation of NO is not favored: (Kc = 4.10 ×10−4 at 2000°C) N2(g) + O2(g) ⇌ 2 NO(g) What...
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