Question

Assume you dissolve 0.235 g of the weak acid benzoic acid, C6H5CO2H, in enough water to make 8.00 x 102 mL of solution and then titrate the solution with 0.128 M NaOH. C6H5CO2H(aq) + OH(aq) → CH3CO2 (aq) + H2O() What are the concentrations of the following ions at the equivalence point? Na+, H307, OH C6H5CO 2. X M Nat X MH30+ X MOH * MC6H5CO2 What is the pH of the solution? Submit Answer

Answer 1

dus) Males of benzoic acid= Mass - 0.2359 Volume 122. 12g/mol = 0.00192 mal Contentration of benzoic acid = moles Volume = 0.00192 molt Oo8L at equivalence haint males of Naon needed= 0.00192 mal. So volume of naon = 0.00192mol 0.015L 00128M Total volume = 0.8 +0.015= 0.8152 Initial volume Naon valime at equivalence paint. males of Cols Coo = 0.00192 mol Concentuation of Cor.600 = 0.00192 mol-0. 0.815L = 2.35mm

I I Calls 100 + H2O - ateqb. 0.00235 ategh 0.00235-x Colicoon ton 0 0 D x2 2992 0000235 1,IIIIIIIII Koc 0.00266-* ko=106810 10 LLLI so 0.00235-x-2 106810-10 = x² 0000235 Y = J 0.00235X10-10XL06 x = 0.776X106 [on] = x= 00776X100M. PM = 14 + log[on ] Pn = 14+ log (60 776 810) = 7.89 Answers E a) Nat = [cots cool] = 2.35X10-3M E 6) 130* = 10th 10.77681056 & 10 29x108M - 1) 0 = 0 716 XỊ0-6 M. d) CHg 600 = 0.00235M eln = 7.89 Thank you.