Question

Part The balanced reaction for the combustion of ethane is shown in the table. You allow 3.3 mol of ethane (CH) to react with 4.1 mol oxygen (O2). using the Simulation, to indicate the amounts of all chemical species for the initial, change, and final conditions Drag the appropriate amounts to their respective targets. View Available Hint(s)

Answer 1

Griven, balanced reaction, 2 CH₂ + 702 4 CO₂ + 6140 o arre allow to and 4.1 mol y and given 3.3 elto mol & Complete the reaction. here we see that, 7 mole of O2 react with 2 mole of the :. 411 mole & O₂ react with (2 x 4.1) mole of laite - 1.17 mole of Catto = 12 mole & He So, here all 4.1 mole & Or is used and only 1.2 mole of Catte is used. stow, from 7 mole for we get 4 mole of co from 4.1 mol of oz we get ( 4 / 3 x 4.1) mole y ca = 2.3 mole of co2 and from 7 mole z oz we get 6 mole of the : : from 42 more of a we get (6/4 x 411) mole of 40 = 3.5 male af ho Honce, the umplete Elf table will be 2 C₂ Ho (2) + 70₂ (9) 4 Q₂ (2) + 6HO(A) Initial - 3.3 mol 4.1 mol 0.0 mol 0.0 moll Change- - 1.2 mol -4.1 mol + 2.3 mol +3.5 mol Final. 2,1 mol 0.0 mol 2.3 mol 3.5 mol