Hollow concrete masonry blocks typically have a net cross sectional area which is at least 25% less than the gross area. (T or F)
A concrete masonry unit has actual gross dimensions of 7-5/8” x 7-5/8” x 7-5/8”. The unit is tested in a compression machine with the following results.
Max. failure load = 98 kips.
Net volume = 348.1 in3
T or F
4. The unit is categorized as solid. _____
5. The gross area compressive strength is 1,631.6 psi. ______
6. The net area compressive strength is 2,147.9 psi. ______
Hollow concrete masonry blocks typically have a net cross sectional area which is at least 25% less than the gross area....
1) The gross area compressive strength is calculated by dividing the load at failure by the gross cross-sectional area of the unit. (T or F) 2)A hollow concrete masonry unit has actual gross dimensions of 7-5/8” x 7-5/8” x 15-5/8”. If the unit fails under a load of 119.14 kips, determine the gross area compressive strength. 3) A concrete masonry unit tested as follows: Saturated mass - 10,089 g Absorption ______% Oven dry mass - 8,893 g Moisture ...
Problem #3 A concrete masonry unit is tested for compressive strength and produces the following results: Failure load- 726 kN Gross area 0.081 m2 Gross volume 0.015 m Net volume = 0.007 m? Is the unit categorized as solid or hollow? Why? What is the compressive strength? Does the compressive strength satisfy the ASTM requirements for load bearing units shown in Table 8.2?