∆G° of the reaction at 298 K is -33.1 kJ
I need help, the chart is the data that needs to be used and calculated. Thank you Thermodynamics (Ν.) (g) + 3H2(g)...
hello may you help me with this. thank you Thermodynamics Gibbs Free energy (N2)(8) + 3H2(8) = 2NH3(e) Thermodynamic parameters Reagent AH', J/K Nitrogen Hydrogen Ammonia 0 0 -46.1 191.5 130.6 192.5 Thermodynamics (N2)(8) + 3H2(g) + 2NH3(e) AG° = AH° – TXAS° product reactant 13 AH° = n;AH;s - In;AH; AS° = { n.5°(each product) - n_S°(each reactant) - sigma = "sum of" n= coefficient of product, n. = coefficient of reactant Thermodynamics Gibbs Free energy Calculate Gibbs free...
help with these please N2(g) + O2(g) 2NO(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: CH (9) +202(g) →CO2(g) + 2H2O(g) de manera en cas de este mai mare de mise en contact tenda Using standard thermodynamic data at 298K, calculate the free energy change when 1.62 moles of CH4(g) react at standard conditions. AGºrx Nz9) +202(g) +2NO2(g) Using standard thermodynamic data at 298K, calculate the free...