At 15 ◦C, the water vapor pressure is 12.79 mmHg. What is the maximum mass of water contained in 2.00·105 L of air at 15...
At 15 ◦C, the water vapor pressure is 12.79 mmHg. What is the maximum mass of water contained in 2.00·105 L of air at 15 ◦C? The molar mass of water is 18.015 g/mol, 1.00 atm = 760 mmHg, T(K) = T(◦C) + 273.
(A) 49.26 kg (B) 2734 g (C) 2566 g (D) 151.8 g (E) 7.91 g
Homework Answers
Given:
P = 12.79 mm Hg
= (12.79/760) atm
= 0.0168 atm
V = 2.00*10^5 L = 200000 L
T = 15.0 oC
= (15.0+273) K
= 288 K
find number of moles using:
P * V = n*R*T
0.0168 atm * 200000 L = n * 0.08206 atm.L/mol.K * 288 K
n = 1.424*10^2 mol
Molar mass of H2O = 18.015 g/mol
use:
mass of H2O,
m = number of mol * molar mass
= 1.424*10^2 mol * 18.015 g/mol
= 2.566*10^3 g
= 2566 g
Answer: C
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