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b. 2.1099 g potassium hydrogen phthalate is added to 20.00 mL of water and titrated with 0.6801 M KOH. How many mil...
When 4.15g of potassium hydrogen phthalate (KHPh M=204.2 g/mol) is titrated with KOH solution and it...
When 4.15g of potassium hydrogen phthalate (KHPh M=204.2 g/mol) is titrated with KOH solution and it takes 46.42 mL of the base to reach the endpoint, calculate the concentration (M) of the KOH solution. I'm confused about the wording of the problem and how to approach it. Does titrated mean just a normal chemical equation problem like KHP + KOH -> ???, or am I suppose to do something special? Also, what does it mean to reach the endpoint? Or...
Mass potassium hydrogen phthalate: .459 g Concentration NaOH solution: .10 M Strong Base titrated...
Mass potassium hydrogen phthalate: .459 g
Concentration NaOH solution: .10 M
Strong Base titrated into weak acid
1. ml base added at equivalence point?
2. ml base added at half-neutralization point 3. moles acid left unreacted at half-neutralization point 3 a. moles salt present at half-neutralization point b. moles of anion of salt present at half-neutralization point 5. ratio of moles of anion to moles of unreacted acid at half-neutralization point 6. . pKa of potassium hydrogen phthalate b. explanation...
A solution of the primary standard potassium hydrogen phthalate, KHC8H4O4, was prepared by dissolving 0.4877 g...
A solution of the primary standard potassium hydrogen phthalate, KHC8H4O4, was prepared by dissolving 0.4877 g of potassium hydrogen phthalate in about 50 mL of water. Titration with a KOH solution required 35.31 mL to reach a phenolphthalein end point. What is the molarity of the KOH solution?
A solution of the primary standard potassium hydrogen phthalate, KHC8H4O4, was prepared by dissolving 0.4877 g...
A solution of the primary standard potassium hydrogen phthalate, KHC8H4O4, was prepared by dissolving 0.4877 g of potassium hydrogen phthalate in about 50 mL of water. Titration with a KOH solution required 36.21 mL to reach a phenolphthalein end point. What is the molarity of the KOH solution?
solution of the primary standard potassium hydrogen phthalate, KHC3H404, was prepared by dissolving 0.4877 g of potassi...
solution of the primary standard potassium hydrogen phthalate, KHC3H404, was prepared by dissolving 0.4877 g of potassium hydrogen phthalate in about 50 mL of water. Titration with a KOH solution required 22.84 mL to reach a phenolphthalein end point. What is the molarity of the KOH solution? Number
A student weighs a sample of potassium hydrogen phthalate (KHP) to prepare a primary standard for...
A student weighs a sample of potassium hydrogen phthalate (KHP) to prepare a primary standard for a titration. She later discovers that the KHP was contaminated with sugar. To determine the amount of KHP in the mixture, she takes 5.942 g of the mixture and make a 100.0 mL solution. The student then titrates 10.00 mL of this solution with a 0.1491 M sodium hydroxide solution. She finds that 13.12 mL of the NaOH solution is needed to reach the...
1. A potassium hydroxide titrant is standardized using potassium hydrogen phthalate. What is the concentration of...
1. A potassium hydroxide titrant is standardized using potassium hydrogen phthalate. What is the concentration of the titrant if 0.6082 g of KHP requires 38.17 mL to reach the phenolphthalein endpoint? 2. What is the concentration of citric acid in an unknown sample if a 10.00 mL aliquot requires 42.78 mL of the above standardized titrant to reach the phenolphthalein endpoint? 3. How many grams of potassium hydrogen phthalate should be used to standardize 0.200 M potassium hydroxide titrant in...
6. Potassium hydrogen phthalate (KHP, KHC8H4O4) is also a good primary standard. 20 mL of NaOH...
6. Potassium hydrogen phthalate (KHP, KHC8H4O4) is also a good primary standard. 20 mL of NaOH was titrated with 0.600 M KHC8H4O4 solution. The data was graphed and the equivalence point was found when 15.5 mL of the standard 0.600 M KHP solution was added. The reaction equation is: a. What is the molar ratio of NaOH:KHC8H4O4? b. What is the molarity of the NaOH solution?
A 0.6745 g sample of Potassium Hydrogen Phthalate (KHP) reacts with 41.75 mL of KOH solution...
A 0.6745 g sample of Potassium Hydrogen Phthalate (KHP) reacts with 41.75 mL of KOH solution for complete neutralization. What is the molarity of the KOH solution? (MW of KHP = 204 g/mol. KHP has one acidic hydrogen.)
6) A 45 ml 0.09 M KOH solution is titrated with 0.11 M HCI: a) How...
6) A 45 ml 0.09 M KOH solution is titrated with 0.11 M HCI: a) How many mL of HCI solution are required to reach the equivalence point? b) What is the pH at the midpoint of the titration? c) What is the pH at the equivalence point?
Mass potassium hydrogen phthalate: .459 g
Concentration NaOH solution: .10 M
Strong Base titrated into weak acid
1. ml base added at equivalence point?
2. ml base added at half-neutralization point 3. moles acid left unreacted at half-neutralization point 3 a. moles salt present at half-neutralization point b. moles of anion of salt present at half-neutralization point 5. ratio of moles of anion to moles of unreacted acid at half-neutralization point 6. . pKa of potassium hydrogen phthalate b. explanation...
solution of the primary standard potassium hydrogen phthalate, KHC3H404, was prepared by dissolving 0.4877 g of potassium hydrogen phthalate in about 50 mL of water. Titration with a KOH solution required 22.84 mL to reach a phenolphthalein end point. What is the molarity of the KOH solution? Number
A student weighs a sample of potassium hydrogen phthalate (KHP) to prepare a primary standard for a titration. She later discovers that the KHP was contaminated with sugar. To determine the amount of KHP in the mixture, she takes 5.942 g of the mixture and make a 100.0 mL solution. The student then titrates 10.00 mL of this solution with a 0.1491 M sodium hydroxide solution. She finds that 13.12 mL of the NaOH solution is needed to reach the...
6) A 45 ml 0.09 M KOH solution is titrated with 0.11 M HCI: a) How many mL of HCI solution are required to reach the equivalence point? b) What is the pH at the midpoint of the titration? c) What is the pH at the equivalence point?
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