Question

h G sometry. Compatibay Modes Help Ginger Tell me what you Homeiniert Draw Design Layout References Mailings Review View do Share Comments Drina Times New Ron 12 AA AA EE BIU. * *AP A. E E 9 . TE. 9 1 . albe AalbC Albice AaBbce AalbCD AalbC Aalbe mga Heading 1 Nom Strong Subtitle Title No Spa G Format Painter . Paragraph Styles 10. A sample of a complex organic protein contains 8.60 x 10" atoms of carbon, 1.89 x 10" atoms of hydrogen, 5.16 x 10" atoms of oxygen, and 2.58 x 10” atoms of nitrogen. This 4.000-gram sample is known to be 0.007140 moles. A) What is the empirical formula of this compound? B) What is the molecular weight of the empirical formula? C) What is the molecular weight of the molecular formula? D) What is the molecular formula? words English (United State) 829 PM Type here to search W AD ENG

Answer 1

27 - 10) 6.023x10 atoms of carbon 12g of carbon obox O 8.60 x 122 automs of carbon 12 x 8.6 X10 > 117139 1139 6.023x1023 mars of Hydrogen= 1x1.89x102 23 0:3149 1 6.023 x 1023 6.023x1623 3.33 X 3 10 0104278 w 0.04278 0.04278 mass of oxygen = 16xs. lbxlo + 1.3719 6.023x1023 mans of Nitrogen = 14 x 2158x10 30.5999 I simple ratio 0:14 27 0.14272 =10 mees of H = 0.314 70.314 = 0.314. – 7134 x 3 = 22 moles of os 1371 -0.08569 = 0.08569 = 2 * 3 = 6 moee of N=0.599 +0.04278 = 0.04278 21 x 3 + 3 A) Empirical formula = Ciola20ca' B) molecular weight dy empirical formula = 280 glempirical mol c) moles mans ndarroas a moderna a 040 560 g/mol molecular weight of molecular formula = 560 g/mol d) molecular formula = (empirical formula) moermans empirical man 26 - 2 molecular ferroula = C HAMPING