if use Methanol as extract solvent to extract activity compound, this reaction need 100c, so choose methanol is good choose or not?
No, methanol is not a good choice because methanol work as extracting solvent at high remptempera(100°C) and compound to be extracted is active. Thus, at such high temperature (100°C), the extracted compound may lost its activity. Also boiling point of methanol is 64°C thus methanol can't be used at 100°C.
if use Methanol as extract solvent to extract activity compound, this reaction need 100c, so choose methanol is good cho...
if use chloroform as solvent to extraction,the hydrophobic compound easy to extract or hydrophilic compound easy to extract? if use Methanol as solvent to extraction,the hydrophobic compound easy to extract or hydrophilic compound easy to extract?
if use ethanol as solvent to extraction,the hydrophobic compound easy to extract or hydrophilic compound easy to extract?compare with methanol
Using the general rule of "like dissolves like", choose the solvent in which the compound will be most soluble: water or benzene (C6H6). ammonia, NH3 KCI hexane, C6H14 iodine, 12 hydrogen bromide, HBr methanol, CH3OH
What does the solvent we use in the extraction assume about the chemical properties of the antibiotic compound?(A)How can we assess whether the antibiotic is present in our extract? (B)What else do we need to learn about the observed antibiotic activity? (C)How to you proceed to study your antibiotic extract?
1. Predict the products of the following reactions (18 points, 3 each) Catalytic KOH methanol/water solvent Catalytic KOH methanol/water solvent Catalytic KOH methanol water solvent Catalye KOH. 1 equivalent NaOCH.CH ethanol solvent I equivalent NaOCH.CH ethanol solvent 2. Write the product of the following reaction and the full mechanism by which it is formed. Clearly show which steps are reversible and which one step is irreversible. (8 points). 1 equivalent NaOCH CH3 cthanol solvent + excess 3. Circle the most...
5. Consider the following solvents for potential use in a Grignard reaction. a) Acetone b) Methanol c) Tetrahydrofuran For each solvent, indicate (yes or no) whether or not the solvent will be suitable for use in a Grignard reaction. If yes, explain why. If no, explain why not, and draw a balanced reaction scheme for the side reaction (NOT the desired reaction) that will likely occur instead
hypothesize why a tertiary alcohol is a good solvent for an sn2 reaction where CsF is the nucleophile and iodide is the leaving group there are various electrophiles that iodide is leaving from who's identities don't seem to matter. from everything I've learned up to now protic solvents are NOT good solvents for sn2 rxns. there have been numerous articles on a research project where 18F is being used for radiolabeling in biological systems and they used tert-amy-alcohol for the...
1 The reaction between (R)-3-chloro-3 methylhexane and methanol, which also serves as solvent for the reaction, gives a mixture of substitution and elimination products. нснен, CH,OH products + CH Draw the stereochemically correct structure(s) for the substitution product(s). (4 pt.) A B Draw all potential regio-isomeric elimination products. (4 pt) C Use curved arrows to show in a stepwise manner the electron flow for the substitution reaction. Stereochemistry counts! (4 pt.) D Use curved arrows to show in a stepwise...
Problems and questions 1. Explain why methanol is an amanic compound but is not considered a hydrocarbon 2. Examine your observations from part. Which of the hydrocarbon samples (methanol is not a hydrocarbon) had the cleanest burning flame? Which had the most smoker so? Why did these luydrocar hans burn differently? 3. Write the complete balanced equation for the combustion of the following compounds: a) methanol b) cyclohexane c) cyclohexene d) toluene 4. Classify each reaction in part Cas an...
SOLVED PROBLEM 7-3 When the following compound is heated in methanol, several different products are formed. Propose mechanisms to account for the four products shown. CH-Br CH heat CH,OH -OCH; + -OCH PARTIAL SOLUTION With no strong base and a good ionizing solvent, we would expect a first-order reaction. But this is a primary alkyl halide, so ionization is difficult unless it rearranges. It might rearrange as it forms, but we'll imagine the cation forming then rearranging. H. Br: CH...