Question

Question 3 Rank the following electronic transitions from most energetic to least. - n = 3 -> n = 2 3rd II. sth CCCC land 1. 6th least energetic 6 -->n-3 na 7 ->n-2 V. 15 (most energetic VI.4th -

Answer 1

Ans :- Correct order is from most energetic to least is : II > III > VI > I > IV > V

Explanation :-

We know that, Energy of the n^th shell is :

E_n = -13.6 Z²/n² eV/atom ...................(1)

I). For n = 3 -> n = 2

E₃-E₂ = -13.6 Z²[1/(3)² - 1/(2)²] = 1.88 Z² eV ............. (4^th​​​​​​​)

II). For n = 4 -> n = 1

E₄-E₁ = -13.6 Z²[1/(4)² - 1/(1)²] = 12.75 Z² eV ............. (1^st most energetic)

III). For n = 2 -> n = 1

E₂-E₁ = -13.6 Z²[1/(2)² - 1/(1)²] = 10.20 Z² eV ............. (2^nd)

IV). For n = 8 -> n = 3

E₈-E₃ = -13.6 Z²[1/(8)² - 1/(3)²] = 1.30 Z² eV............. (5^th​​​​​​​)

V). For n = 6 -> n = 3

E₆-E₃ = -13.6 Z²[1/(6)² - 1/(3)²] = 1.13 Z² eV ............. (6^th least energetic)​​​​​​​)

VI). For n = 7 -> n = 2

E₇-E₂ = -13.6 Z²[1/(7)² - 1/(2)²] = 3.12 Z² eV............. (3^rd​​​​​​​)