Dear student,
GIVEN PROBLEM can be solved by titration equation and i have solved the question.Please go through it and if there are any further doubts or something is not clear please feel free to comment here
Commercial hydrochloric acid is 12.4 M. A chemist wants to prepare 0.334 M HCI. How many milliliters (ml) of the ac...
How many milliliters of a 0,40 M solution of hydrochloric acid (HCI) are necessary to neutralize 33 mL of a 0.20 M barium hydroxide (Ba(OH)2 solution? 16.5 mL 20 ml 66 mL O 33 mL O 10.5 mL
How many milliliters of 0.550 M hydrochloric acid are needed to react with 15.00 mL of 0.217 M Mg(OH)2? (Answer 11.8 mL, make sure you do the right work) RARE 2HCl(aq) + Mg(OH)2 (aq) + MgCl2(aq) + 2H20(1)
How many milliliters of 0.210 M BaCl2 must be added to 12.4 mL of 0.418 M Na2SO4 to give complete reaction between their solutes? Volume of Ba2+ solution? One of the solids present in photographic film is silver bromide, AgBr. Suppose we want to prepare AgBr by the following precipitation reaction. 2AgNO3(aq) + CaBr2(aq) → 2AgBr(s) + Ca(NO3)2(aq) How many milliliters of 0.123 M CaBr2 solution must be used to react with the solute in 51.1 mL of 0.160 M...
A chemist titrates 190.0 mL of a 0.4393 M hydrochloric acid (HCI) solution with 0.1456 M NaOH solution at 25 °C. Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added. pH = [] Х 5 ? Calculating the pH of a weak acid titrated with a strong base An analytical chemist is titrating...
A chemist must prepare 250.0 ml of hydrochloric acid solution with a pH of 1.80 at 25°C. He will do this in three steps: Fila 250.0 ml. volumetric flask about halfway with distilled water. • Measure out a small volume of concentrated (6.0 M) stock hydrochloric acid solution and add it to the flask. . Fill the flask to the mark with distilled water, Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second...
How could you make 2.5 L of 0.10 M hydrochloric acid? Question 10 (1 point) How could you make 2.5 L of 0.10 M hydrochloric acid? Hint: This is a dilution. How many moles of HCI in 2.5L of 0.1M? Use the fact that M = ? that M - n moles so # of moles n = M, V =.. O dilute 59.4 mL of 3.0 M HCl to 2.5 L with water O dilute 0.25 L of pure...
How many milliliters of concentrated hydrochloric acid solution (36.0% HCl by mass, density = 1.18 g/mL) are required to produce 10.0 L of a solution that has a pH of 2.22?
Part A How many milliliters of concentrated hydrochloric acid solution (36.0% HCl by mass, density = 1.18 g/ml) are required to produce 16.0 L of a solution that has a pH of 2.197
Question 24 (2.57 points) How many milliliters of 0.550 M hydrochloric acid are needed to react with 15.00 mL of 0.217 M CSOH? HCl(aq) + CsOH(aq) → CsCl(aq) + H2011) O 0.169 mL 5.92 mL 38.0 mL 0.0263 mL
How much of a 21.0 M hydrochloric acid solution would you dilute to prepare 50.00 mL of 9.00 M HCl?