Question

In the pictures below, a bug has landed on the rim of a jelly jar and is moving around the rim. The location where the b...

In the pictures below, a bug has landed on the rim of a jelly jar and is moving around the rim. The location where the bug initially lands is described and its angular speed is given. Impose a coordinate system with the origin at the center of the circle of motion. In each of the cases, answer these questions.

Case 1 Case 2
WebAssign Plot WebAssign Plot
Case 3
WebAssign Plot

(a) Find an angle θ0 in standard central position that gives the bug's initial location. (In some cases, this is the angle given in the picture.)

Case 1      θ0 =

rad

Case 2      θ0 =

rad

Case 3      θ0 =

rad

θ(t) = θ0 + ωt.

(b) The location angle of the bug at time t is given by the formula

Plug in the values for θ0 and ω to explicitly obtain a formula for θ(t).

Case 1      θ(t) =
Case 2      θ(t) =
Case 3      θ(t) =



(c) Find the coordinates of the bug at time t.

Case 1      (x, y) =
leftparen1.gif
  
rightparen1.gif
Case 2      (x, y) =
leftparen1.gif
  
rightparen1.gif
Case 3      (x, y) =
leftparen1.gif
  
rightparen1.gif

(d) What are the coordinates of the bug after 1 second? After 0 seconds? After 3 seconds? After 22 seconds? (Round your answers to three decimal places.)

Case 1      1 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     0 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     3 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     22 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
Case 2      1 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     0 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     3 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     22 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
Case 3      1 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     0 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     3 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
     22 sec      (x, y) =
leftparen1.gif
  
rightparen1.gif
0 0
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Answer #1

(a) to = initial angulas positions Case I o = 0.8 rad = 0.8 rad Case a do = t rad = 3.14 god Case D to = -0.5 rad = 2.64 rad(d) Coordinates of bug after t=1 sec, osec, 3 sec, 22 sec Casel. I see (x,y) = /2003 (0.8+ 4 ) 2 sin (0.8 + x)) = (-1.171 in,Case 11 I see o sec (x,y) = (2005 (T-0.5-4x), 2 sin (K-0.5-2 22x)) = (0.640 in 1.900 in) (2,y) = (2005 (-0:5), a sin(4-0-5))

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