Question

Use the Refereaces to access important values if needed for this question Salt bridge A concentration cell similar to the one shown is composed of two Cd electrodes and solutions of different Cd+ concentrations. The left compartment contains 0.895 M Cd+ and the right compartment contains 1.30 M Cd Calculate the cell potential for this reaction at 298 K volts In this cadmium concentration cell, the compartment on the left is the and the compartment on the right is the

Answer 1

The given electrochemical cell is a concentration cell.

Here, we will use the Nernst equation:

RI In 72 cell cell

$E^{0}$cell = Standard Electrochemical potential

n = number of electrons involved in the reaction

Q =reaction Quotient

8.314 298 -cell = 0 295484.56 n(0.895/1.30)

Ecell = 4.84X10-3V

Left compartment is Cathode as electrons will move from lower concentration to higher concentration, which makes Right compartment an Anode.