Question 57 is given below
Fitness (w) of each phenotype is calculated by dividing each phenotype's survival rate by the highest survival rate among the 3 phenotypes.
(a) Fitness:
Solid-brown - 10/60 =0.167 (BB)
brown and green stripes - 60/60 = 1 (Bb)
Solid-green - 50/60 = 0.833 (bb)
Mean fitness = p2wBB + 2pqwBb + q2 wbb
Total individuals = 802
p (for BB) = 195/802 = 0.243
q (for bb) = 198/802 = 0.247
Mean fitness = 0.159
(b) Frequency for BB = pxp = 0.059
Frequency for bb = qxq = 0.061
Frequency for Bb = 2xpxq = 0.12
Question 57 is given below 23 You continue your studies of snails. The woodland population from question 57 were moved...