Question

All pins are in double shear, and each has a diameter of 15 mm . P=7 kN . (Figure 1)

Determine the average shear stress in the pin at A , B and C

Answer 1

Draw the free body diagram 0.5 m 05m 15m 2m 1.5m For the equilibrium of AB Apply the equilibrium of moment about point A. (Px0.5)+(6Px2)+(3Px 4)+(Px5.5)-Fc св 18 ,-58.33 kN Apply the force equilibrium along x direction 4 A 46.664 kN

Apply the force equilibrium along y direction. 11P 0 4, 11P-EB 3 A 11x7-58.33 A.-42 kN Calculate the resultant reaction force at point A 46.6642 +422 - 62.78 kN Calculate the average share stress at point A (62.78x10')/2 x(0.015) -177.631x106 Pa 4 -177.631 MPa Calculate the average share stress at point B and C. (58.33x10')/2 1 x (0.015) 4 - 165.04x106 Pa -165.04 MPa