Question

Beam AB is supported as shown in the figure. Tie rod (1) has a diameter of 58 mm ,and it is attached at B and Cwith 24 mm diameter double-shear pin connections. The pin connection at A consists of a 40 mm diameter single-shear pin. The pins at A, B, and C each have an ultimate shear strength of 500 MPа ,and tie rod (1) has a yield strength of 280 МРPа . A uniformly distributed load of W is applied to the beam as shown. Dimensions are 4.50 a = b 0.42 m , and c = 1.30 . A minimum factor of safety of 2.5 is required for all components. What is the maximum loading that may be applied to the structure? 2.5 is required for all components. What is the maximum loading W that may be applied to the structure? (1) y B b A Wmax kN/m eTextbook and Media Hint

Answer 1

ta(5 sino 4.5 FBc 1.3 m e - 16.11 3 For Cose O42 m E HA A VA 4.5 AX C2801 Givem, Yield strength tiebar Bc 280 500 N/mm strength of pins Uuimate she ar . ield load obar Bc X BC 4 Tx58 x 2 80 cel2 z 73978 2.24 N = 739.7 8 2 kN. Capucity f pin at ULti mate shear CIs B and 2 DT x 2 Y = 500 x 24-x 2 For double 452 389 N shear 452.389 KN. N N CD

is equal ro bar As tensim develo ped BC deve loped in the pin B and C the shear allowable tension n BC hence maximum 4gield capacity of Capacity of pin . bar BC the minimum shear am d KN 452. 389 452-389 Permissible FBC .. Fac tor of Safety 452.389 2.5 180.956 KN figre e ferring the above Nouw EM = O. A 4.5 Sin 9x 4.5+ Wx 4.5 x Co s xO.42 = -Fec in(t-113)4.5 180.956 xCos(16.113) x o.42-180.956 s 4.5 + Wx 4.5 x 29.53 2 KN/ MAximum allow able to ad to be applied is Ams 29.532 KN/m