Question

Pipe (2) is supported by a pin at bracket C and by tie rod (1). The structure supports a load P at pin B. Tie rod (1) has a diameter of 11 mm and an allowable normal stress of 165 MPa. Pipe (2) has an outside diameter of 48 mm, a wall thickness of 7 mm, and an allowable normal stress of 75 MPa. Assume x₁ = 2.9 m, x₂ = 1.5 m, and y₁ = 3.9 m. Determine the maximum load P_max that can be supported by the structure without exceeding either allowable normal stress.

Pipe (2) is supported by a pin at bracket C and by tie rod (1). The structure supports a load P at pin B. Tie rod (1) has a diameter of 11 mm and an allowable normal stress of 165 MPa. Pipe (2) has an outside diameter of 48 mm, a wall thickness of 7 mm, and an allowable normal stress of 75 MPa. Assume x1 = 2.9 m, x2 = 1.5 m, and y1 = 3.9 m. Determine the maximum load Pmax that can be supported by the structure without exceeding either allowable normal stress. B 1 (1) с Answer: Pmax = kN The number of significant digits is set to 3; the tolerance is +/-1%

Answer 1

Grien P Papipe 2 to tre roda Gall= 75ma , (sal)&= 165Mpa. do = 48mm dee slimm. t=7mm. X1=2.9m X2=1.5m Y1 = 3.9m. To find : - Pmax. Cuithout exceeding allowable stresses) FBD at point B Hom Opple 15 Yr 39 22 Orole = tini (26) Opgle = 68.96 53:367 168076 tam OslA = 4 = FBA "FB con 3.9 2-9 orfa FE 201 OBIA - tum (9.34 غي Assumption ! - Forces to right Upward are EFxzo Positive OBIA=53:36 positive P+Fc (0368.96- FACO153-36-0 Efyao - F Sin 53.36-Fe sin 68.9650 FA sin 53.36=fe sin 68.96

FCF) Sin 68.96 sin 53.36 FAE1163) Fc. Condition: 1: williout exceed allowable stress of Tieriod. bal Aroa. 165 = FA -> FA= 15.68 KN 1 (11) If FA = 15168 them fA=-(-163)Fc (fc =-13-48kN Ptfclos68-96-FA Cos 53.360 . P+(-13:48)60368.96- 15.6860553-36-0 P- 4184 – 9.36=0. P=14:197kN condition @ :-without escceed allaccable stress of pipe. Gal) pipe = Fc 198 Area Fc 175- T(482-342) di= 48-2(7) 34 fe= 67.62 KN If Fc = 67.62}<w, then FA :-(1.163) Fe. FA=-78.64 kN] Ptfclos 68.96-FALOS 53.3620. P+67.62656896 - (-78:69) 60353,3620 p +24.28 +46.9320 P=-71620 KN

both conditions considering beyond 14.197kN In conditimo Pmax = 14.1976 N if i't goes will occur in Tie rod. failure will definetely . 8 so in condition ☆ Pmax= 11.20 if that much load problided. failure so Pmane = 14-197KN if the maximum that Can applied witrout exceeding allowabé stresit Tie rod Gave detailed solution, please upvote If doult please comment.