Question

Chapter 1, Reserve Problem 003 Pipe (2) is supported by a pin at bracket C and by tie rod (1). The structure supports a load P at pin B. Tie rod (1) has a diameter of 12 mm and an allowable normal stress of 130 MPa. Pipe (2) has an outside diameter of 58 mm, a wall thickness of 6 mm, and an allowable normal stress of 95 MPa. Assume x1 = 2.8 m, x2 = 1.3 m, and y1 = 3.5 m. Determine the maximum load Pmax that can be supported by the structure without exceeding either allowable normal stress. B Р (2) X1 Answer: Pmax= KN The number of significant digits is set to 3; the tolerance is +/-1% Click if you would like to Show Work for this question: Open Show Work

Answer 1

Given Datar => rod diameter = 12mm allowable normal SHCM 130 MPa 2 piper outside diameter 58mm wall thicknes Gmm allowable normal stres a 5 MPa 8 P A 4 = 3.5m 91-2.8m 22-13m 0 = tan" ( 13 ) tant 20.374 3.5 C tana) - 38.660 da tant' ( 7 ) at Joint P: FBC FBA EFXzo z> +P = FRA sind sino FBC FBc sin (20 370) - FBA Sin (38.66): - p.

0.348 FBC 0.624 FBA = P. 0.624 FBA 0.348 FBC =P - { fy=0 => FBc CosO+ FBA Cold = 0 FBC - FBA Cosa Coso FBA. Cos (38.68) cos ( 20:370) FBC 11 -0.833 FBA From 0.624 FRA - 0.348 (-0.833 FRA] = P 0.624 FRA & 0.289 FBA =P Р FBA . 0.913 FBA 1.095p (rod). FBC 11 - 0833* 1.095 P FBC -0.912 p C Pipe)

(1) rod Force 1.095 P dia 12mm Gallois 130 MPa TI X122 113109 mm? we know that PIA 130 11 1.095P 113.09 pa 130 x 113.09 13426 N 1.095 Pa 13.42 6 IN ( M) pipe ; Force = 0.912 P . 6-a5 MPa. dout 58mm t 6mm din 58 - 2x6 = u 6mm 2 Hlo (do ² di 2) = 7 (582-462) A 980-17 mm P r - A an = 0.912 P 980.17 P= 95 x980.17 102101N 0.912

P= 102.101 KN both values Pmat is of minimum Prat 13.426 KN