Question

Tries remaining Pants out of 10 p u esto What is the pH of a solution of the buffer containing 0.004 M HCNO and 0.062 M NaCNO

0 0
Add a comment Improve this question Transcribed image text
Answer #1

13)

Ka = 2*10^-4

pKa = - log (Ka)

= - log(2*10^-4)

= 3.699

use:

pH = pKa + log {[conjugate base]/[acid]}

= 3.699+ log {6.2*10^-2/4*10^-3}

= 4.889

Answer: 4.89

14)

Ka = 5.88*10^-6

pKa = - log (Ka)

= - log(5.88*10^-6)

= 5.231

use:

pH = pKa + log {[conjugate base]/[acid]}

4.51 = 5.231+log {[C5H5N]/[HC5H5N+]}

log {[C5H5N]/[HC5H5N+]} = -0.7206

[C5H5N]/[HC5H5N+] = 0.1903

Answer: 0.190

Add a comment
Know the answer?
Add Answer to:
Tries remaining Pants out of 10 p u esto What is the pH of a solution of the buffer containing 0.004 M HCNO and 0.06...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT