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A 0.334-kg mass is attached to a spring with a force constant of 54.9 N/m Part A If the mass is displaced 0.200 m from equili

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m=0.334 Kg K = 54.9 N/m Xo = 0.2 m x = 0. 131 By Conservation of energy, 1 KG = Į Kasa + L mva. mv = k oo - Kxca. (9132 (0.27

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