<Chapter 13 Problem 13.48 10 of 10 > an Review A 0.303-kg mass is attached to a spring with a force constant...

Question

Question

Answer 1

Answer #1

SOLUTION :

Angular speed (w) = sqrt( K / m)

w = sqrt(52.8/0.303)

w = 13.2rad/sec.

Now at any displacement 'x' its speed will be given by

v = w*sqrt( A^2 - x^2)

Where A is its amplitude.

v = 13.2 * sqrt( 0.260^2 - 0.111^2)

v = 3.1 m/s

Answer 2

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