The graph of 1/X(t) versus time can be drawn as follows.
Equation of the line: 1/X(t) = 0.13078*t + 0.94801
Where 't' is the time of reaction.
The reaction order is 2.
Compare the above equation with the second-order rate law, i.e. 1/X(t) = kt + 1/X(0)
Then, you will get the rate constant (k) = 0.13078 M-1.min-1
this is matlab.. updated, this is not matlab. 2. Saponification batch reactor. In a saponification reaction that t...
For a constant volume batch reactor, solve for the temporal concentration profiles, e.g., CA(t) and CBt) at each initial condition (IC). Given) Reversible elementary reaction kA (forward) B kB (backward) dC - -k^C4kCB dt dC = k,C-k,C B dt k 0.0001(s) k 0.00005(s1) = 0 (mol/dm at t 0, CAo = 0.5 (mol/dm') and CBo IC 1. at t-0, CAO 0.5 (mol/dm2) and CB0 = 0.2 (mol/dm' 2. IC Using any ODE solver, solve the coupled ODES for two initial...
For a constant volume batch reactor, solve for the temporal concentration profiles, e.g. CA(t) and CB(t) at each initial condition (IC) Given) Reversible elementary reaction kA (forward) A B ka (backward) dCkCkC dt dCkC-kC, dt k 0.0001s) k0.00005(s 1 IC at t-0, CAO= 0.5 (mol/dm) and CBo 0 (mol/dm IC at t-0, CAO 0.5 (mol/dm') and CBo 0.2 (mol/dm 2. Using any ODE solver, solve the coupled ODEs for two initial conditions Need to submit graphs (CA and CB vs...