The enthalpy change for the following reaction is -318 kJ. OF2(g) + H2O(g) --> O2(g) + 2HF(g) a) To analyze the react...
The enthalpy change for the following reaction is -318 kJ.
OF2(g) + H2O(g) --> O2(g) + 2HF(g)
a) To analyze the reaction, first draw Lewis structures for all reactant and product molecules.
b) Estimate the O-F bond energy in OF2(g) , using tabulated bond energies (linked above) for the remaining bonds.
Bond data for question two can be found in a references chart by googling bond energy (will not allow photo upload)
H - O = 463kJ
O=O = 498kJ
H-F = 565kJ
Homework Answers
![lewis structure + H T: + HC • CH örö + 2H-F AH = BE of reautants – BE of produts -318 = (2x0-F + 2x0-H]-[0=0+2x H-E] -318= (2](http://img.homeworklib.com/questions/ccc463b0-1413-11ea-8e91-9786f809bee0.png?x-oss-process=image/resize,w_560)
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