Question #4: Now let's do the same for the opposite enantiomer, rank the substituents based on the Cahn-Ingold-Prelog (...
Question #4: Now let's do the same for the opposite enantiomer, rank the substituents based on the Cahn-Ingold-Prelog (R and S) ranking convention. 1 2 3
Rank the substituents shown below in order of Cahn-Ingold-Prelog priorities (1 = highest priority group, 4 = lowest priority group). -C(CH3)3 -CH(CH3)2 -CH3 -CH2CH3 Submit Answer Retry Entire Group 1 more group attempt remaining
Rank the set of substituents below in order of priority according to the Cahn-Ingold-Prelog sequence rules. Submit Answer Try Another Version 1 item attempt remaining
Rank the set of substituents below in order of priority according to the Cahn-Ingold-Prelog sequence rules. W-C-CH_BW=CHCH. Dw-cios b o (a) —C=CH (b) -CH=CH2 (c) —C(CH3)3 (d)
Rank the substituents shown below in order of Cahn-Ingold-Prelog priorities (1 -highest priority group, 4-lowest priority group) Submit Answer Retry Entire Group 9 more group attempts remaining
COST0301386 Rank the following groups in terms of their priority according to the Cahn Ingold Prelog system of priorities. Give the chest ranking group a priority of 1 and the lowest ranking group a n y of 4
Rank the following substituents from lowest to highest priority according to the Cahn-Ingold-Prelog rules. =O -NH2 - CHI3 -OH E, B, A, D A, D, E, B OD, A, E,B B, E, D, A
Use the Cahn-Ingold-Prelog rules to rank the following groups in terms of priority 2. Use the Cahn-Ingold-Prelog rules to rank the following groups. In terms of priority 3. Use the Cahn-Ingold-Preiog rules to rank the following groups in terms of priority
3. Assign Cahn-Ingold-Prelog rankings to the substituents below (4 pts) -CO2CH3, --COCHz, -CH OCH3, -CH2CH3
Using Cahn-Ingold-Prelog
convention assign the relative priority to each group on the chiral
center in the following molecule. With 1 being the highest priority
and 4 being the lowest priority.
Question 10 0/1pc Using Cahn-Ingold-Prelog convention assign the relative priority to each group on the chiral center in the following molecule. With 1 being the highest priority and 4 being the lowest priority. HC D CH3 HC A OH OB < 0