Question

TABLE 2-4 PARTIAL PRESSURE OF AMMONIA OVER AMMONIA- WATER SOLUTIONS AT 20°C Data from Perry, op. cit., p. 171) NH3 Partial Pressure, Hg o'HaHN 0.05 31.7 0.10 69.6 0.15 114 0.20 166 0.25 227

The partial pressure of ammonia in air-ammonia mixtures in equilibrium with its aqueous solution at 20°C is given in Table 2. Using these data, and neglecting the vapor pressure of water and the solubility of air in water, construct an equilibrium diagram using mole ratios with Y_A = moles NH₃/mole air and X_A = moles NH₃/mole H₂O as coordinates. (a) If 10 moles of gas, of composition Y = 0.3, are contacted with 10 moles of a solution of composition X = 0.1, what will be the composition of the resulting phases at equilibrium? The process is isothermal.

Hint: start by converting Table 2 to a new table of Y_A vs X_A à Plot curve and your answer has to be on that curve ….use mass balances to arrive at the answer …

Answer 1

ANSWER 31.9 31.9 4- 760 31.9 760 mm total premure foY oD 5 Q NH3 X 61 fox 69.6 .1008 foy O1463 for 0.2989 166 for 4 O.4263 foy o10 NH920 010 59 for O15 0 1588 fox O.al18 for Oa644 obgoe

moles at 0.3 a) to Soluton at 14 ba lance matesir al + L Gy + L Let moles G to- to to 1o XO 3 motes water -10 -1oX0.1 9 09 from .9 0.3 9.09 0 - 1. t9 t 0 42

and Guilibrtum Curve tnteuection The ofesultingphases at gives Бе Compo sition Guilibnum B0 O.193 O.1903