We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
i need help with 4a, b, c, d 4. A merry-go-round with a diameter of 12 meters, rotates with an angular velocity of...
A disk-shaped merry-go-round of radius 2.13 m and mass 185 kg rotates freely with an angular speed of 0.631 rev/s. A 59.4 kg person running tangential to the rim of the merry-go-round at 3.31 m/s jumps onto ts rim and holds on. Before jumping on the merry-go- round, the person was moving in the same direction as the merry-go-round's rim Part A What is the final angular speed of the merry-go-round? 2220 Symbols rad/s Submit Request Answer
7.An 80.0 kg person rotates and undergoes uniform circular motion with a constant angular velocity of 8.0 rad/s 2.0m from the center of a merry-go-round. a) What is the person’s centripetal acceleration? b) What is the centripetal force this person experiences?
A 3.9-m-diameter merry-go-round is rotating freely with an angular velocity of 0.80 rad/s . Its total moment of inertia is 1350 kg⋅m2 . Four people standing on the ground, each of mass 68 kg , suddenly step onto the edge of the merry-go-round. What is the angular velocity of the merry-go-round now?
A 4.5-m-diameter merry-go-round is rotating freely with an angular velocity of 0.84 rad/s . Its total moment of inertia is 1700 kg⋅m2 . Four people standing on the ground, each of mass 68 kg , suddenly step onto the edge of the merry-go-round. What is the angular velocity of the merry-go-round now? What if the people were on it initially and then jumped off in a radial direction (relative to the merry-go-round)?
A 4.4-m-diameter merry-go-round is rotating freely with an angular velocity of 0.90 rad. Its total moment of inertia is 1360 kg⋅m2 . Four people standing on the ground, each of mass 62 kg , suddenly step onto the edge of the merry-go-round. A) What is the angular velocity of the merry-go-round now? B) What if the people were on it initially and then jumped off in a radial direction (relative to the merry-go-round)?
A 3.5 kg cat is near the edge of a 6.5 m diameter merry-go-round in a playground. A man pushes and accelerates the merry-go-round from rest at a uniform rate of 0.75 rad/s2. The cat clings tighter and tighter, but can only hold on with 150 N of force and eventually flies off. At what tangential velocity will the cat fly off? This occurs when the needed centripetal force exceeds what the cat's claws can supply.
A girl (named Mary? Get it?) stands at the outer edge of a merry-go-round at distance 2.3m from the center. The merry-go-round is rotating at 22 rpm. The girl has a mass of 30kg, and the merry-go-round has a moment of inertia of 1300kgm^2 (a) What is the moment of inertia of the girl as she rotates around the center of the merry-go-round? (b) What is the angular velocity of the merry-go-round? rad/s (c) What is the total moment of...
A merry-go-round starts from rest and accelerates uniformly over 19.5 s to a final angular velocity of 6.75 rev/min. (a) Find the maximum linear speed of a person sitting on the merry-go-round 6.50 m from the center. (b) Find the person's maximum radial acceleration. (c) Find the angular acceleration of the merry-go-round. (d) Find the person's tangential acceleration.
Question 7, chap 11, sect 10. part of 10 points A merry-go-round rotates at the rate of 0.11 rad/s with a(n) 85.3 kg man standing at a point 2.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0.71 m from the center? Assume that the merry-go-round is a solid 7.41 x 102 kg cylinder with a radius of 3.80 m. Answer in units of rad/s.
Question (part 1 of 2) A merry-go-round rotates at the rate of 0.29 rev/s with an 79 kg man standing at a point 2.9 m from the axis of rotation. What is the new angular speed when the man walks to a point 1 m from the center? Consider the merry-go-round is a solid 44 kg cylinder of radius of 2.9 m Answer in units of rad/s. Question (part 2 of 2) What is the change in kinetic energy due...