Question (part 1 of 2) A merry-go-round rotates at the rate of 0.29 rev/s with an...
Part 1-2 A merry-go-round rotates at the rate of 0.26 rev/s with an 86 kg man standing at a point 2.1 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 60 kg cylinder of radius of 2.1 m Answer in units of rad/s. .Part 2-2 What is the change in kinetic energy due to this movement? Answer in units...
023 (part 1 of 2) 10.0 point A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4:11 from the ax of rotation : What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.19 rev/s with an 89 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 38 kg cylinder of radius of 1.5 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
A merry-go-round rotates at the rate of 0.38 rev/s with an 98 kg man standing at a point 1.8 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 93 kg cylinder of radius of 1.8 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change in kinetic energy due to this movement?...
Question 7, chap 11, sect 10. part of 10 points A merry-go-round rotates at the rate of 0.11 rad/s with a(n) 85.3 kg man standing at a point 2.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0.71 m from the center? Assume that the merry-go-round is a solid 7.41 x 102 kg cylinder with a radius of 3.80 m. Answer in units of rad/s.
A merry-go-round rotates at the rate of 0.15 rev/s with an 85-kg man standing at a point 2.0 m from the axis of rotation. (a) What is the new angular speed when the man walks to a point 0.9 m from the center? Assume that the merry-go-round is a solid 25-kg cylinder of radius 2.0 m. (b) Calculate the change in kinetic energy due to this movement. J How do you account for this change in kinetic energy? -Work is...
A disk-shaped merry-go-round of radius 2.13 m and mass 185 kg rotates freely with an angular speed of 0.631 rev/s. A 59.4 kg person running tangential to the rim of the merry-go-round at 3.31 m/s jumps onto ts rim and holds on. Before jumping on the merry-go- round, the person was moving in the same direction as the merry-go-round's rim Part A What is the final angular speed of the merry-go-round? 2220 Symbols rad/s Submit Request Answer
A 40.0-kg child running at 3.00 m/s suddenly jumps onto a stationary playground merry-go-round at a distance 1.50 m from the axis of rotation of the merry-go-round. The child is traveling tangential to the edge of the merry-go-round just before jumping on. The moment of inertia about its axis of rotation is 600 kg ? m2 and very little friction at its rotation axis. What is the angular speed of the merry-go-round just after the child has jumped onto it?...
A merry go round (a disk I=1/2MR^2, M=200 kg, R=2 m) rotates at 0.4 rad/s. A child with a mass of 60 kg is dropped onto the merry go round at a distance of 1.5 m from the axis of rotation. How fast is the child moving after it comes to turn with the merry go round? A) 0.16 m/s B) 0.30 m/s C) 0.45 m/s D) 0.66 m/s