023 (part 1 of 2) 10.0 point A merry-go-round rotates at the rate of 0.39 rev/s...

Question

Question

Answer 1

Answer #1

Answer 2

Similar Homework Help Questions

023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.39 rev/s...

023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.19 rev/s...

023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.19 rev/s with an 89 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 38 kg cylinder of radius of 1.5 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
A merry-go-round rotates at the rate of 0.38 rev/s with an 98 kg man standing at...

A merry-go-round rotates at the rate of 0.38 rev/s with an 98 kg man standing at a point 1.8 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 93 kg cylinder of radius of 1.8 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change in kinetic energy due to this movement?...

Question (part 1 of 2) A merry-go-round rotates at the rate of 0.29 rev/s with an...

Question (part 1 of 2) A merry-go-round rotates at the rate of 0.29 rev/s with an 79 kg man standing at a point 2.9 m from the axis of rotation. What is the new angular speed when the man walks to a point 1 m from the center? Consider the merry-go-round is a solid 44 kg cylinder of radius of 2.9 m Answer in units of rad/s. Question (part 2 of 2) What is the change in kinetic energy due...
Part 1-2 A merry-go-round rotates at the rate of 0.26 rev/s with an 86 kg man...

Part 1-2 A merry-go-round rotates at the rate of 0.26 rev/s with an 86 kg man standing at a point 2.1 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 60 kg cylinder of radius of 2.1 m Answer in units of rad/s. .Part 2-2 What is the change in kinetic energy due to this movement? Answer in units...
A merry-go-round rotates at the rate of 0.15 rev/s with an 85-kg man standing at a...

A merry-go-round rotates at the rate of 0.15 rev/s with an 85-kg man standing at a point 2.0 m from the axis of rotation. (a) What is the new angular speed when the man walks to a point 0.9 m from the center? Assume that the merry-go-round is a solid 25-kg cylinder of radius 2.0 m. (b) Calculate the change in kinetic energy due to this movement. J How do you account for this change in kinetic energy? -Work is...

Question 7, chap 11, sect 10. part of 10 points A merry-go-round rotates at the rate...

Question 7, chap 11, sect 10. part of 10 points A merry-go-round rotates at the rate of 0.11 rad/s with a(n) 85.3 kg man standing at a point 2.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0.71 m from the center? Assume that the merry-go-round is a solid 7.41 x 102 kg cylinder with a radius of 3.80 m. Answer in units of rad/s.
A merry go round (a disk I=1/2MR^2, M=200 kg, R=2 m) rotates at 0.4 rad/s. A...

A merry go round (a disk I=1/2MR^2, M=200 kg, R=2 m) rotates at 0.4 rad/s. A child with a mass of 60 kg is dropped onto the merry go round at a distance of 1.5 m from the axis of rotation. How fast is the child moving after it comes to turn with the merry go round? A) 0.16 m/s B) 0.30 m/s C) 0.45 m/s D) 0.66 m/s
A disk-shaped merry-go-round of radius 2.13 m and mass 185 kg rotates freely with an angular...

A disk-shaped merry-go-round of radius 2.13 m and mass 185 kg rotates freely with an angular speed of 0.631 rev/s. A 59.4 kg person running tangential to the rim of the merry-go-round at 3.31 m/s jumps onto ts rim and holds on. Before jumping on the merry-go- round, the person was moving in the same direction as the merry-go-round's rim Part A What is the final angular speed of the merry-go-round? 2220 Symbols rad/s Submit Request Answer

A 19.75 kg child is riding a playground merry-go-round that is rotating at 41.1 rev/min. What...

A 19.75 kg child is riding a playground merry-go-round that is rotating at 41.1 rev/min. What net force is acting on her if she is standing on the merry-go-round 1.15 m from its center in newtons? The net force in this situation is sometimes called "centripetal force". What net force (in N) is acting on her if she is standing on an amusement park merry-go-round that rotates at 2.2 rpm and she is 9.3 m from its center? How many...