A merry-go-round rotates at the rate of 0.15 rev/s with an 85-kg man standing at a point 2.0 m from the axis of rotation.
(a) What is the new angular speed when the man walks to a point
0.9 m from the center? Assume that the merry-go-round is a solid
25-kg cylinder of radius 2.0 m.
(b) Calculate the change in kinetic energy due to this
movement.
J
How do you account for this change in kinetic energy?
-Work is done by the man on the system as he moves towards the center.
-Work is done by the merry-go-round on the man as he moves towards the center. -Wind resistance varies as the square of the speed.
-The moment arm of the man about the axis of rotation decreases.
A merry-go-round rotates at the rate of 0.15 rev/s with an 85-kg man standing at a...
A merry-go-round rotates at the rate of 0.38 rev/s with an 98 kg man standing at a point 1.8 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 93 kg cylinder of radius of 1.8 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change in kinetic energy due to this movement?...
Part 1-2 A merry-go-round rotates at the rate of 0.26 rev/s with an 86 kg man standing at a point 2.1 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 60 kg cylinder of radius of 2.1 m Answer in units of rad/s. .Part 2-2 What is the change in kinetic energy due to this movement? Answer in units...
Question (part 1 of 2) A merry-go-round rotates at the rate of 0.29 rev/s with an 79 kg man standing at a point 2.9 m from the axis of rotation. What is the new angular speed when the man walks to a point 1 m from the center? Consider the merry-go-round is a solid 44 kg cylinder of radius of 2.9 m Answer in units of rad/s. Question (part 2 of 2) What is the change in kinetic energy due...
023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.19 rev/s with an 89 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 38 kg cylinder of radius of 1.5 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
023 (part 1 of 2) 10.0 point A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4:11 from the ax of rotation : What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
Question 7, chap 11, sect 10. part of 10 points A merry-go-round rotates at the rate of 0.11 rad/s with a(n) 85.3 kg man standing at a point 2.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0.71 m from the center? Assume that the merry-go-round is a solid 7.41 x 102 kg cylinder with a radius of 3.80 m. Answer in units of rad/s.
A man of mass 75kg stands at the center of a rotating merry-go-round platform of radius 3.0 m and moment of inertia 920 kgm^2. The platform rotates without friction with angular velocity 2.0 rad/s. The man walks radially to the edge of the platform. Calculate: the angular velocity of the system when the man reaches the edge, and the change in the kinetic energy of the system.
A merry-go-round modeled as a disk of mass 100 kg and radius 2.0 m is rotating around a frictionless vertical axle. After a person of mass 60 kg jumps onto the merry-go-round, the system’s angular speed decreases to 2.0 rad/s. If the person walks slowly from the edge toward the center, find the change in the system’s rotational kinetic energy caused by her movement to 0.5 m from the center.
A disk-shaped merry-go-round of radius 2.63 m and mass 155 kg rotates freely with an angular speed of 0.692 rev/s. A 59.4 kg person running tangential to the rim of the merry-go-round at 3.27 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round's rim. (a) Does the kinetic energy of the system increase, decrease, or stay the same when the person jumps on the merry-go-round?...