Part 1-2 A merry-go-round rotates at the rate of 0.26 rev/s with an 86 kg man...
A merry-go-round rotates at the rate of 0.38 rev/s with an 98 kg man standing at a point 1.8 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 93 kg cylinder of radius of 1.8 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change in kinetic energy due to this movement?...
Question (part 1 of 2) A merry-go-round rotates at the rate of 0.29 rev/s with an 79 kg man standing at a point 2.9 m from the axis of rotation. What is the new angular speed when the man walks to a point 1 m from the center? Consider the merry-go-round is a solid 44 kg cylinder of radius of 2.9 m Answer in units of rad/s. Question (part 2 of 2) What is the change in kinetic energy due...
023 (part 1 of 2) 10.0 point A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4:11 from the ax of rotation : What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
023 (part 1 of 2) 10.0 points A merry-go-round rotates at the rate of 0.19 rev/s with an 89 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 38 kg cylinder of radius of 1.5 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
A merry-go-round rotates at the rate of 0.15 rev/s with an 85-kg man standing at a point 2.0 m from the axis of rotation. (a) What is the new angular speed when the man walks to a point 0.9 m from the center? Assume that the merry-go-round is a solid 25-kg cylinder of radius 2.0 m. (b) Calculate the change in kinetic energy due to this movement. J How do you account for this change in kinetic energy? -Work is...
Question 7, chap 11, sect 10. part of 10 points A merry-go-round rotates at the rate of 0.11 rad/s with a(n) 85.3 kg man standing at a point 2.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0.71 m from the center? Assume that the merry-go-round is a solid 7.41 x 102 kg cylinder with a radius of 3.80 m. Answer in units of rad/s.
A disk-shaped merry-go-round of radius 2.13 m and mass 185 kg rotates freely with an angular speed of 0.631 rev/s. A 59.4 kg person running tangential to the rim of the merry-go-round at 3.31 m/s jumps onto ts rim and holds on. Before jumping on the merry-go- round, the person was moving in the same direction as the merry-go-round's rim Part A What is the final angular speed of the merry-go-round? 2220 Symbols rad/s Submit Request Answer
A man of mass 75kg stands at the center of a rotating merry-go-round platform of radius 3.0 m and moment of inertia 920 kgm^2. The platform rotates without friction with angular velocity 2.0 rad/s. The man walks radially to the edge of the platform. Calculate: the angular velocity of the system when the man reaches the edge, and the change in the kinetic energy of the system.
A 40.0-kg child running at 3.00 m/s suddenly jumps onto a stationary playground merry-go-round at a distance 1.50 m from the axis of rotation of the merry-go-round. The child is traveling tangential to the edge of the merry-go-round just before jumping on. The moment of inertia about its axis of rotation is 600 kg ? m2 and very little friction at its rotation axis. What is the angular speed of the merry-go-round just after the child has jumped onto it?...