Question

H2(9)+I2(9)2 HI(9) At the temperature the engineer picks, the equilibrium constant K, for this reaction is 0.73. The engineer charges ("fills") three reaction vessels with hydrogen and iodine, and lets the reaction begin. She then measures the composition of the n inside each vessel from time to time. Her first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time she measures the compositions. reaction vessel compound pressure expected change in pressure O4 decrease O (no change) Ot increase н, 2.97 atm increase 4 decrease (no change) 4.27 atm A A decrease (no change) 3.05 atm t increase HI Ot increase O (no change) 4 decrease н, 2.49 atm O4 decrease T increase (no change) 12 3.79 atm B O (no change) O4 decrease t increase 4.01 atm нI O decrease (no change) Ot increase н, 2.48 atm O decrease O (no change) t increase 3.78 atm C (no change) decrease 4.03 atm T increase HI Submit I Don't Know Rinhts Beservedi

Answer 1

H2(9)+I2(9)2 HI(9) At the temperature the engineer picks, the equilibrium constant K, for this reaction is 0.73. The engineer charges ("fills") three reaction vessels with hydrogen and iodine, and lets the reaction begin. She then measures the composition of the n inside each vessel from time to time. Her first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time she measures the compositions. reaction vessel compound pressure expected change in pressure O4 decrease Ot increase н, 2.97 atm (no change) O4 decrease t increase (no change) 4.27 atm A A decrease (no change) 3.05 atm t increase HI 4 decrease O (no change) t increase н, 2.49 atm decrease (no change) increase 12 3.79 atm B decrease O (no change) t increase 4.01 atm нI O decrease (no change) t increase н, 2.48 atm O decrease O (no change) t increase 3.78 atm C (no change) 4 decrease 4.03 atm t increase HI Submit I Don't Know Rinhts Beservedi

Explanation :

Kp = 0.73

Qp = P²HI / P_H2 x P_I2

    = (3.05)^2 / (2.97 x 4.27)

Qp = 0.73

here Kp = Qp . so no change

B)

Qp = 1.70

Kp < Qp .

so products decreases , reactants increases