When using the K-map to find the equations for DA and DB for the problem down below, how can you tell which variable is supposed to be for the row and columns?
How can I tell if the rows for the 2x4 k-maps would be dealing with "A" while the columns would be dealing with "Bx"? Does it even matter how I set up the K-map?
---------------------------------------------------------------------------------------------------------------------------------------------------------
Design a sequential circuit with two D flip-flops A and B, and one input x_in.
When x_in = 0, the state of the circuit remains the same. When
x_in =1, the circuit
goes through the state transitions from 00 to 11, to 01, to 10,
back to 00, and repeats.
I think in question ....the order is from 00 to 01 and to 10 ,to 11
But it is different given there.
Coming to k maps , we can take any variable to rows and columns ...we will get the same answer.
Setting up the k map is very easy, just follow the rules of taking correct digits for the variables .
And variables may be in any order ,it will gives the same answer
When using the K-map to find the equations for DA and DB for the problem down below, how can you tell which variable is...
Its logic design my sequence is 127605 i need help with all this pages please and thank you 27 60 Experiment 4 Six-State Up-Down Counter 1 Objective To become familiar with the design procedures of a counter, which are applicable to the design of other synchronous sequential circuits. 2 Problem description A six-state up-down counter is to be designed. Three flip-flops with outputs Q2,Qi and Qo are required in the design. As shown in Figure 1, the counter is initialized...
Need help part B and C please. Thank you . CDA3201·Intro to Logic Desig Lab Assignment Name: Grade: 20 5) 120] At right is the state dingram for a Moore sequential 1 01.10 АО circuit which monitors two inputs XiXo. When the two inputs XiXo are 00, the output Z toggles at every clock When the two inputs XiXo are 11, the output Z toggles at every other clock. When the two inputs XiXo are different, the output Z holds...