Question

Question 11

1 Point

The K_sp of Ag₂CO₃ is 8.11 x 10^-12. What is the maximum Ag⁺ ion concentration possible if the carbonate ion concentration is 1.14 x 10^-4 M?

Select the correct answer

1. 1.14 x 10^-4 M

2. 2.67 x 10^-4 M

3. 2.24 x 10^-4 M

4. 7.11 x 10^-8 M

Answer 1

the Ag₂CO₃ will dissociates as

Ag₂CO₃$\rightleftharpoons$ 2Ag⁺ + CO₃^2-  

and the Ksp for this reaction is

Ksp = [Ag⁺]²[CO₃^2-]

Now we have

Ksp = 8.11 $\times$ 10^-12

[CO₃^2-] = 1.14 $\times$ 10^-4 M

hence by using above Ksp formula we get

Ksp = [Ag⁺]²[CO₃^2-]

8.11 $\times$ 10^-12 = [Ag⁺]²$\times$ 1.14 $\times$ 10^-4

[Ag⁺]² = 8.11 $\times$ 10^-12 / 1.14 $\times$ 10^-4

= 7.11 $\times$ 10^-8

by taking square roots on bothe sides we get

[Ag⁺] = 2.67 $\times$ 10^-4 M

so our answer is

[Ag⁺] = 2.67 $\times$ 10^-4 M